Nimbus

I am doing a Chemistry lab, and I am trying to figure out how much energy is released by the warm water as it is cooled through 47 degrees celsius and 44.4 degrees celsius. What and how would I need to do to solve this?

Heat= mass X specific heat X change in temp

2 Responses

1. Brittany Says:
   February 16th, 2010 at 1:55 pm

   heat= mass x specific heat x change in temperature

   specific heat of water= 4.184 joules per gram degrees celsius

   change in temperature would be 3.4 degrees celsius

   all you need is the mass of the water if you have it and plug all of these in and that should give you the heat released.
   References :
   myself

2. science teacher Says:
   February 16th, 2010 at 2:38 pm

   Heat= mass X specific heat X change in temp
   References :

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